4^(2^x-1)=2^(x^2)+48

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Solution for 4^(2^x-1)=2^(x^2)+48 equation: 



4^(2^x-1)=2^(x^2)+48

We move all terms to the left:

4^(2^x-1)-(2^(x^2)+48)=0

We get rid of parentheses

4^(2^x-1)-2^x^2-48=0

We move all terms containing x to the left, all other terms to the right

4^(2^x-1)-2^x^2=48

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